php教程

number_format

(PHP 4, PHP 5, PHP 7)

number_format — 以千位分隔符方式格式化一个数字

说明

number_format ( float $number [, int $decimals = 0 ] ) : string
number_format ( float $number , int $decimals = 0 , string $dec_point = "." , string $thousands_sep = "," ) : string

本函数可以接受1个、2个或者4个参数（注意：不能是3个）:

如果只提供第一个参数，number的小数部分会被去掉 并且每个千位分隔符都是英文小写逗号","

如果提供两个参数，number将保留小数点后的位数到你设定的值，其余同楼上

如果提供了四个参数，number 将保留decimals个长度的小数部分, 小数点被替换为dec_point，千位分隔符替换为thousands_sep

参数

number

你要格式化的数字

decimals

要保留的小数位数

dec_point

指定小数点显示的字符

thousands_sep

指定千位分隔符显示的字符

返回值

格式化以后的 number.

更新日志

版本 说明
5.4.0 This function now supports multiple bytes in dec_point and thousands_sep. Only the first byte of each separator was used in older versions.

范例

Example #1 number_format() Example

For instance, French notation usually use two decimals, comma (',') as decimal separator, and space (' ') as thousand separator. The following example demonstrates various way to format a number:

<?php

$number = 1234.56;

// english notation (default)
$english_format_number = number_format($number);
// 1,235

// French notation
$nombre_format_francais = number_format($number, 2, ',', ' ');
// 1 234,56

$number = 1234.5678;

// english notation without thousands separator
$english_format_number = number_format($number, 2, '.', '');
// 1234.57

?>

更新日志

版本 说明
7.2.0 number_format() 现在无法返回 -0，之前可能返回 -0，因为 number 可能会是 -0.01。

参见

User Contributed Notes

mail at igor dot vodka 23-May-2019 11:56
Please be careful with stm555 at hotmail dot com's solution.
If you pass some little negative number (-1 < $number < 0) such as -0.01, the integer part would be converted to 0, so that the sign is eventually lost.
Here is a fixed version:

<?php
      function number_format_unlimited_precision($number,$decimal = '.')
      {
           $broken_number = explode('.', abs($number));
           $sign = $number < 0 ? '-' : '';
           return $sign.number_format($broken_number[0]).$decimal.$broken_number[1];
      }
?>
Lio 30-Nov-2017 01:43
Be carreful, when you're using French notation
means : number_format(124.25, 2 , ',' , ' ') with ',' as dec_point,

Don't forget to specify thousands_sep that default is ',' to another value, otherwise function will return null.
ismavolk at gmail dot com 01-Dec-2016 11:16
Number format not round

public static function numberFormatNotRound($n, $decs, $decPoint = '.', $thousandsSep = ',')
{
    $decs ++;
    $n = number_format($n, $decs, $decPoint, $thousandsSep);
    $n = substr($n, 0, -1);

    return $n;
}
patribezek at gmail dot com 04-Mar-2016 07:06
To separate big numbers like the spanish language you can do this:
Tis example is based on facebook followers:

number_format ($infoF  , 0 , ' , ' ,  '.');

it will output:

//1.187.037

instead of comas.
vlad at blox dot ru 05-Feb-2016 11:43
This function is used for reformatting already formatted numbers.
<?php
function formatNumber($number, $format=[], $oldDecimalSeparator=",.·'", $multiplier=1)
{
    /**
    $format — the array of formatting options, details in the example.
    $oldDecimalSeparator — decimal separator used in the $number. If the separator can meet different characters, then you need to record them all, for example: ',.'.
    $multiplier — typically used to adjust prices up or down.
    */
    if ($format) {
        $format += ['numOfDecimals' => 0, 'decimalSeparator' => '.', 'thousandSeparator' => '']; # Default format
        # Find decimal separator
        # The decimal separator is the one that is the last and does not occur more than once
        if ($letters = str_replace(' ', '', $number)) { # Replace spaces
            if ($letters = preg_replace('/^-/', '', $letters)) { # Remove minus
                if ($letters = preg_replace('/[0-9]/', '', $letters)) { # Get all non digits
                    $lastletter = substr($letters, -1); # Returns last char
                    if (substr_count($letters, $lastletter) == 1) {
                        if (strpos($oldDecimalSeparator, $lastletter)  !== false)
                            $oldDecimalSep = $lastletter;
                        else
                            return $number;
                    }
                }
            }
        }
        $number = preg_replace('/[^0-9-]/', '', $number); # Remove all non digits except 'minus'
        if ($oldDecimalSep)
            $number = str_replace($oldDecimalSep, '.', $number); # Format to float
        if ($multiplier != 1)
            $number = $number * $multiplier;
        # Convert float to new format
        $number = number_format($number,
            $format['numOfDecimals'],
            $format['decimalSeparator'],
            $format['thousandSeparator']
        ); 
    }
    return $number;   
}

/**
Example. Formatting data in which the decimal separator can occur as the comma and dot. Formatting into Russian format: -12 345,67
*/
echo formatNumber($number, [
    'numOfDecimals' => 2,
    'decimalSeparator' => ',',
    'thousandSeparator' => '&nbsp;'
], ',.');

?>
besciualexandru at gmail dot com 29-Oct-2015 08:09
// Here is a function that produces the same output as number_format() but also works with numbers bigger than 2^53.

function a_number_format($number_in_iso_format, $no_of_decimals=3, $decimals_separator='.', $thousands_separator='', $digits_grouping=3){
    // Check input variables
    if (!is_numeric($number_in_iso_format)){
        error_log("Warning! Wrong parameter type supplied in my_number_format() function. Parameter \$number_in_iso_format is not a number.");
        return false;
    }
    if (!is_numeric($no_of_decimals)){
        error_log("Warning! Wrong parameter type supplied in my_number_format() function. Parameter \$no_of_decimals is not a number.");
        return false;
    }
    if (!is_numeric($digits_grouping)){
        error_log("Warning! Wrong parameter type supplied in my_number_format() function. Parameter \$digits_grouping is not a number.");
        return false;
    }
   
   
    // Prepare variables
    $no_of_decimals = $no_of_decimals * 1;
   
   
    // Explode the string received after DOT sign (this is the ISO separator of decimals)
    $aux = explode(".", $number_in_iso_format);
    // Extract decimal and integer parts
    $integer_part = $aux[0];
    $decimal_part = isset($aux[1]) ? $aux[1] : '';
   
    // Adjust decimal part (increase it, or minimize it)
    if ($no_of_decimals > 0){
        // Check actual size of decimal_part
        // If its length is smaller than number of decimals, add trailing zeros, otherwise round it
        if (strlen($decimal_part) < $no_of_decimals){
            $decimal_part = str_pad($decimal_part, $no_of_decimals, "0");
        } else {
            $decimal_part = substr($decimal_part, 0, $no_of_decimals);
        }
    } else {
        // Completely eliminate the decimals, if there $no_of_decimals is a negative number
        $decimals_separator = '';
        $decimal_part       = '';
    }
   
    // Format the integer part (digits grouping)
    if ($digits_grouping > 0){
        $aux = strrev($integer_part);
        $integer_part = '';
        for ($i=strlen($aux)-1; $i >= 0 ; $i--){
            if ( $i % $digits_grouping == 0 && $i != 0){
                $integer_part .= "{$aux[$i]}{$thousands_separator}";
            } else {
                $integer_part .= $aux[$i];           
            }
        }
    }
   
    $processed_number = "{$integer_part}{$decimals_separator}{$decimal_part}";
    return $processed_number;
}

$original_number= 9223372036854775805;
echo a_number_format($original_number, 4, '.',"'",3);
// Outputs: 9'223'372'036'854'775'805.1230
kryss dot schuenemann at egba dot ba dot gov dot br 06-Jun-2015 01:07
//Cep Brasil
    function getCEP($cep){
        return number_format(substr($cep, 0, 5),0,"",".").'-'.substr($cep, 5, 3);
    }
//Saida 12.345-67
mobi dot lenoe at gmail dot com 28-Oct-2013 08:13
I'd like to comment to the old notes of "stm555" and "woodynadobhar".
They wrote about "number_format_unlimited_precision()".
I guess many of us need that kind of function, which is the almost same function as number_format but don't round a number.

Does Anyone know any new solution in a recent PHP version?

...
If no, how about the following function? (I fixed somethings like bugs of the function in the old comment.)
<?php
function number_format_unchanged_precision($number, $dec_point='.', $thousands_sep=','){
    if($dec_point==$thousands_sep){
        trigger_error('2 parameters for ' . __METHOD__ . '() have the same value, that is "' . $dec_point . '" for $dec_point and $thousands_sep', E_USER_WARNING);
        // It corresponds "PHP Warning:  Wrong parameter count for number_format()", which occurs when you use $dec_point without $thousands_sep to number_format().
    }
    if(preg_match('{\.\d+}', $number, $matches)===1){
        $decimals = strlen($matches[0]) - 1;
    }else{
        $decimals = 0;
    }
    return number_format($number, $decimals, $dec_point, $thousands_sep);
}
var_dump(number_format_unchanged_precision(1234.5678, ',', '.'));
var_dump(number_format_unchanged_precision(1234.5678, ','));
var_dump(number_format_unchanged_precision(12345678));
var_dump(number_format_unchanged_precision(-0.5678, ',', '.'));  // It occurred a bug with the function in the old comment.
?>
output is:
    string(10) "1.234,5678"
    PHP Warning:  2 parameters for number_format_unchanged_precision() have the same value, that is "," for $dec_point and $thousands_sep in...
    string(10) "1,234,5678"
    string(10) "12,345,678"
    string(7) "-0,5678"
tomislav at firmus-grupa dot hr 03-Mar-2013 05:01
When apply number_format on number with separator on thousands, result is wrong. This function accept number of any format
<?php
function format_price($number,$decPlaces,$decSep,$thouSep){
       
    //$number - number for format
    //$decPlaces - number of decimal places
    //$decSep - separator for decimals
    //$thouSep - separator for thousands
   
    //first remove all white spaces
    $number=preg_replace('/\s+/', '',$number);
    //split string into array
    $numberArr = str_split($number);
    //reverse array and not preserve key, keys will help to find decimal place
    $numberArrRev=array_reverse($numberArr);
   
    //find first occurrence of non number character, that will be a decimal place
    //store $key into variable $decPointIsHere
    foreach ($numberArrRev as $key => $value) {
        if(!is_numeric($value)){
            if($decPointIsHere==""){
                $decPointIsHere=$key;
            }           
        }
    }
   
    //decimal comma or whatever it is replace with dot
    //$decPointIsHere is the key of the element that will contain decimal separator dot
    if($decPointIsHere!=""){
        $numberArrRev[$decPointIsHere]=".";
    }
   
    //again check through array for non numerical characters but skipping allready processed keys
    //if is not number remove from array
   
    foreach ($numberArrRev as $key => $value) {
        if(!is_numeric($value) && $key>$decPointIsHere){
            unset($numberArrRev[$key]);           
        }
    }
   
    //reverse back, at the start reversed array $numberArrRev to $numberArr
    $numberArr=array_reverse($numberArrRev);   
   
    //create string from array
    $numberClean=implode("",$numberArr);
       
    // apply php number_format function
    return number_format($numberClean,$decPlaces,$decSep,$thouSep);
   
}

echo format_price("1 225 552, 55",2,',',' ')."<br>";
echo format_price("1.225.552, 55",2,',',' ')."<br>";
echo format_price("1'225'552. 55",2,',',' ')."<br>";
echo format_price("1225552.55",2,',',' ')."<br>";
?>
all results are: 1 225 552,55
vgurudev at nikshepa dot com 04-May-2012 08:37
<?php

    function convertNumberToWordsForIndia($number){
        //A function to convert numbers into Indian readable words with Cores, Lakhs and Thousands.
        $words = array(
        '0'=> '' ,'1'=> 'one' ,'2'=> 'two' ,'3' => 'three','4' => 'four','5' => 'five',
        '6' => 'six','7' => 'seven','8' => 'eight','9' => 'nine','10' => 'ten',
        '11' => 'eleven','12' => 'twelve','13' => 'thirteen','14' => 'fouteen','15' => 'fifteen',
        '16' => 'sixteen','17' => 'seventeen','18' => 'eighteen','19' => 'nineteen','20' => 'twenty',
        '30' => 'thirty','40' => 'fourty','50' => 'fifty','60' => 'sixty','70' => 'seventy',
        '80' => 'eighty','90' => 'ninty');
       
        //First find the length of the number
        $number_length = strlen($number);
        //Initialize an empty array
        $number_array = array(0,0,0,0,0,0,0,0,0);       
        $received_number_array = array();
       
        //Store all received numbers into an array
        for($i=0;$i<$number_length;$i++){    $received_number_array[$i] = substr($number,$i,1);    }

        //Populate the empty array with the numbers received - most critical operation
        for($i=9-$number_length,$j=0;$i<9;$i++,$j++){ $number_array[$i] = $received_number_array[$j]; }
        $number_to_words_string = "";       
        //Finding out whether it is teen ? and then multiplying by 10, example 17 is seventeen, so if 1 is preceeded with 7 multiply 1 by 10 and add 7 to it.
        for($i=0,$j=1;$i<9;$i++,$j++){
            if($i==0 || $i==2 || $i==4 || $i==7){
                if($number_array[$i]=="1"){
                    $number_array[$j] = 10+$number_array[$j];
                    $number_array[$i] = 0;
                }       
            }
        }
       
        $value = "";
        for($i=0;$i<9;$i++){
            if($i==0 || $i==2 || $i==4 || $i==7){    $value = $number_array[$i]*10; }
            else{ $value = $number_array[$i];    }           
            if($value!=0){ $number_to_words_string.= $words["$value"]." "; }
            if($i==1 && $value!=0){    $number_to_words_string.= "Crores "; }
            if($i==3 && $value!=0){    $number_to_words_string.= "Lakhs ";    }
            if($i==5 && $value!=0){    $number_to_words_string.= "Thousand "; }
            if($i==6 && $value!=0){    $number_to_words_string.= "Hundred &amp; "; }
        }
        if($number_length>9){ $number_to_words_string = "Sorry This does not support more than 99 Crores"; }
        return ucwords(strtolower("Indian Rupees ".$number_to_words_string)." Only.");
    }

    echo convertNumberToWordsForIndia("987654321");
   
    //Output ==> Indian Rupees Ninty Eight Crores Seventy Six Lakhs Fifty Four Thousand Three Hundred & Twenty One Only.
?>
before_i_sleep at hotmail dot co dot uk 27-Apr-2012 02:26
As many people state the number_format function will round. Now if you're like me and you don't want stuff to round (and the functions below do not work for you) you can try a little regex:

<?php

function convert_size_human($size){
    $unit=array('','KB','MB','GB','TB','PB');
    $byte_size = $size/pow(1024,($i=floor(log($size,1024))));

    if(is_really_int($byte_size)){
        return $byte_size.' '.$unit[$i];
    }else{
        preg_match('/^[0-9]+\.[0-9]{2}/', $byte_size, $matches);
        return $matches[0].' '.$unit[$i];
    }
}

?>

The regex used when the number is not an int ensures that 3.99887 GB comes out as 3.99 GB instead of 4GB as it does from number_format or the functions below.
liviu andrei (bls) 18-Nov-2011 08:10
To prevent the rounding that occurs when next digit after last significant decimal is 5 (mentioned by several people below):

<?php
function fnumber_format($number, $decimals='', $sep1='', $sep2='') {

        if (($number * pow(10 , $decimals + 1) % 10 ) == 5)  //if next not significant digit is 5
            $number -= pow(10 , -($decimals+1));

        return number_format($number, $decimals, $sep1, $sep2);

}

$t=7.15;
echo $t . " | " . number_format($t, 1, '.', ',') .  " | " . fnumber_format($t, 1, '.', ',') . "\n\n";
//result is: 7.15 | 7.2 | 7.1

$t=7.3215;
echo $t . " | " . number_format($t, 3, '.', ',') .  " | " . fnumber_format($t, 3, '.', ',') . "\n\n";
//result is: 7.3215 | 7.322 | 7.321
} ?>

have fun!
robmann at gmx dot li 05-May-2011 04:02
Here a function to filter exponential notation like 6e-06. Turn it to 0,000006 for comfortable reading. Supporting various number of decimals!

<?php
function easy_number_format($number, $dec_point, $thousands_sep)
{
    $number = rtrim(sprintf('%f', $number), "0");
    if (fmod($nummer, 1) != 0) {                     
        $array_int_dec = explode('.', $number);
    } else {
        $array_int_dec= array(strlen($nummer), 0);
    }
    (strlen($array_int_dec[1]) < 2) ? ($decimals = 2) : ($decimals = strlen($array_int_dec[1]));
    return number_format($number, $decimals, $dec_point, $thousands_sep);
}
?>

The maximum accuracy depends on sprintf('%f', $number). In this case 6 decimals. Expand it to 10 with '%.10f'.
Ali Okan YKSEL 26-Oct-2010 02:47
function formats numbers of datetime type,

<?php
$_GET["zaman"]="1983-8-28 5:5:5";

function _parseDatetimeToList($datetimeStr) { //datetime format: Y-m-d H-i-s
    $datetimeArray=explode(" ", $datetimeStr);
    $dateArray=explode("-",$datetimeArray[0]);
    $year=str_pad($dateArray[0], 2, "0", STR_PAD_LEFT);
    $month=str_pad($dateArray[1], 2, "0", STR_PAD_LEFT);
    $day=str_pad($dateArray[2], 2, "0", STR_PAD_LEFT);
    $timeArray=explode(":",$datetimeArray[1]);
    $hour=str_pad($timeArray[0], 2, "0", STR_PAD_LEFT);
    $minute=str_pad($timeArray[1], 2, "0", STR_PAD_LEFT);
    $second=str_pad($timeArray[2], 2, "0", STR_PAD_LEFT);
    return array($year, $month, $day, $hour, $minute, $second);
}

list($year, $month, $day, $hour, $minute, $second) = _parseDatetimeToList($_GET["zaman"]);  // 1983-1-28 5:5:5
?>
Ricky *@* Mataka [com] 15-Oct-2010 11:10
Hey Guys, dont know if this is the best way but it worked for me as i faced a problem where I had to split any large number > then 10K into into to exact split amounts.. so i wrote this this to do the trick.. hope it helps some one out there!

<?php
function divide22($num)
{
  $valone = intval($num / 2);
  $valtwo = $valone;
  if (($num % 2) > 0) $valtwo++;
  return array($valone, $valtwo);
}
function split2vals($num,$split_amount)
{ 
  $store=array();
  $times = round(($num/$split_amount));
  $amount= $num/$times;  
  for($i=0;$i<$times;$i++)
  {
     $store[]=round($amount);
  }
  foreach($store as $index=>$value)
  {
    if($value>$split_amount)
    {
       $get_splits=divide22($value);
       //unset the split
       unset($store[$index]);
       $store[]=$get_splits[0];
       $store[]=$get_splits[1];
    }
  }
  $sum=array_sum($store);
 
  if($sum > $num){
    $sub=$sum-$num;
      $end=end($store);
    array_pop($store);
    $store[]=$end-$sub;
  }
  if($sum < $num){
    $store[]=($num-$sum); 
  }
  return $store;
}

//USAGE

$check_amount=50567.83;
echo 'Input Split = '.$check_amount.'<br><br>';
$store=split2vals($check_amount,10000);
print_r($store);
$sum=array_sum($store);
echo '<br><br>Should Be Exact ='. $sum;
exit();
?>
Cody G. 08-Aug-2010 02:06
Sometimes, I'm sure, you guys are looking for a way to do the exact opposite of this function: convert a comma-filled number back to normal decimal.
Here's a quick code that popped into my head today:

<?php
 $mynumstr = "100,000,000.75";
 $mynum = doubleval(str_replace(",","",$mynumstr));
?>

This is especially useful when validating user input. Some people like to include comma's with their numbers.
Some also like to include the dollar-sign when entering prices. Here's a modification:

<?php
 $mynumstr = '$100,000,000.25';
 $arr1 = array(',','$');
 $arr2 = array('','');
 $mynum = doubleval(str_replace($arr1,$arr2,$mynumstr));
 //The arrays had to be defined in a
 //  variable to shorten statement.
?>

Okay, that takes care of it, I use the PHP4 array compatibility update to remove several characters.
Don't forget to either use single-quotes or escape the dollar-sign!

~Cody G.
me dot nosp at m dot unreal4u dot com 08-Jul-2010 12:36
Maybe it is documented, but I just missed it. However, a comment is always useful.

An array will always be converted into 1, so, if you have:

<?php
$my_array = array(55);
echo number_format($my_array,0,',','.');
// 1
var_dump(number_format($my_array,2,',','.'));
// string(4) "1,00"
?>

Since it took me a while to figure it out, I hope this will save somebody's time.

Greetings !!
isedc at yahoo dot com 29-Mar-2010 12:38
Some programmers may have scripts that use the number_format function twice on a variable.  However, if a number is 4 or more digits, using the function twice with only the decimals parameter will lose part of the value that follows the thousands separator.

<?php
$var = number_format(2234,2);
$var = number_format($var,2);
echo $var;
# Expected Output: 2,234.00
# Actual Output: 2.00
?>

To fix, remove the thousands separator by setting the decimal point and thousands separator parameters like so:

<?php
$var = number_format(2234,2,'.','');
$var = number_format($var,2,'.','');
echo $var;
# Expected Output: 2234.00
# Actual Output: 2234.00
?>

If it's 3 digits or less, then it works normally with only the decimals parameter since there is no thousands separator.

<?php
$var = number_format(123,2);
$var = number_format($var,2);
echo $var;
# Expected Output: 123.00
# Actual Output: 123.00
?>
dipu dot ashok dot 17 at gmail dot com 28-Mar-2010 01:18
function to convert numbers to words
indian: thousand,lakh,crore
Note: function can only convert nos upto 99 crores

<?php
 $words = array('0'=> '' ,'1'=> 'one' ,'2'=> 'two' ,'3' => 'three','4' => 'four','5' => 'five','6' => 'six','7' => 'seven','8' => 'eight','9' => 'nine','10' => 'ten','11' => 'eleven','12' => 'twelve','13' => 'thirteen','14' => 'fouteen','15' => 'fifteen','16' => 'sixteen','17' => 'seventeen','18' => 'eighteen','19' => 'nineteen','20' => 'twenty','30' => 'thirty','40' => 'fourty','50' => 'fifty','60' => 'sixty','70' => 'seventy','80' => 'eighty','90' => 'ninty','100' => 'hundred &','1000' => 'thousand','100000' => 'lakh','10000000' => 'crore');
function no_to_words($no)
{    global $words;
    if($no == 0)
        return ' ';
    else {           $novalue='';$highno=$no;$remainno=0;$value=100;$value1=1000;       
            while($no>=100)    {
                if(($value <= $no) &&($no  < $value1))    {
                $novalue=$words["$value"];
                $highno = (int)($no/$value);
                $remainno = $no % $value;
                break;
                }
                $value= $value1;
                $value1 = $value * 100;
            }       
          if(array_key_exists("$highno",$words))
              return $words["$highno"]." ".$novalue." ".no_to_words($remainno);
          else {
             $unit=$highno%10;
             $ten =(int)($highno/10)*10;            
             return $words["$ten"]." ".$words["$unit"]." ".$novalue." ".no_to_words($remainno);
           }
    }
}
echo no_to_words(999978987);

?>
info at daniel-marschall dot de 22-May-2009 12:54
In my function my_number_format() [shown below] there was a bug.

If a negative number which is smaller than 1 was entered (-0,...), then the result was wrongly positive because +0 is equal to -0 (the content of $tmp[0] which was interpretet as numeric value).

Here is the corrected version:

<?php

function my_number_format($number, $dec_point, $thousands_sep)
{
    $was_neg = $number < 0; // Because +0 == -0
    $number = abs($number);

    $tmp = explode('.', $number);
    $out = number_format($tmp[0], 0, $dec_point, $thousands_sep);
    if (isset($tmp[1])) $out .= $dec_point.$tmp[1];

    if ($was_neg) $out = "-$out";

    return $out;
}

?>

Thanks to Federico Cassinelli for the bug report.



[EDIT BY danbrown AT php DOT net: The original note follows.]

Let's say we got the number $inp = 1234.56

By using

<?php
return number_format($inp, 2, ',', '.');
?>

you can get the German format 1.234,56. (Comma as decimal separator and point as thousand separator)

But I have a problem with that: I want to add commas as thousand separators and change the decimal-separator (this could also be done with str_replace), but I do not want to change the amount of fractional digits!

But since the 2nd argument of number_format is necessary to enter the 3rd and 4th argument, this cannot be done with number_format. You have to change the fractional digits with this function.

But I want that 1234.56 changes into 1.234,56 and 1234.567890123456 changes into 1.234,567890123456

So, I created following function, that doesn't change the amount of fractional digits:

<?php
function my_number_format($number, $dec_point, $thousands_sep)
{
  $tmp = explode('.', $number);
  $out = number_format($tmp[0], 0, $dec_point, $thousands_sep);
  if (isset($tmp[1])) $out .= $dec_point.$tmp[1];

  return $out;
}
?>
james at bandit dot co.nz 26-Mar-2009 09:03
Outputs a human readable number.

<?php
    #    Output easy-to-read numbers
    #    by james at bandit.co.nz
    function bd_nice_number($n) {
        // first strip any formatting;
        $n = (0+str_replace(",","",$n));
       
        // is this a number?
        if(!is_numeric($n)) return false;
       
        // now filter it;
        if($n>1000000000000) return round(($n/1000000000000),1).' trillion';
        else if($n>1000000000) return round(($n/1000000000),1).' billion';
        else if($n>1000000) return round(($n/1000000),1).' million';
        else if($n>1000) return round(($n/1000),1).' thousand';
       
        return number_format($n);
    }
?>

Outputs:

247,704,360 -> 247.7 million
866,965,260,000 -> 867 billion
IMSoP 18-Mar-2009 02:36
I'm not sure if this is the right place anyway, but "ben at last dot fm"'s ordinal function can be simplified further by removing the redundant "floor" (the result of floor is still a float, it's the "%" that's converting to int) and outer switch.

Note that this version also returns the number with the suffix on the end, not just the suffix.

<?php
function ordinal($num)
{
    // Special case "teenth"
    if ( ($num / 10) % 10 != 1 )
    {
        // Handle 1st, 2nd, 3rd
        switch( $num % 10 )
        {
            case 1: return $num . 'st';
            case 2: return $num . 'nd';
            case 3: return $num . 'rd'; 
        }
    }
    // Everything else is "nth"
    return $num . 'th';
}
?>
Barbara 26-Jan-2009 11:04
I was looking for a SIMPLE way to format currency and account for negative values while not losing the calculation properties of my number.  Here's my function - it's not rocket science, but maybe can help someone along the way.

<?php
function wims_currency($number) {
   if ($number < 0) {
     $print_number = "($ " . str_replace('-', '', number_format ($number, 2, ".", ",")) . ")";
    } else {
     $print_number = "$ " .  number_format ($number, 2, ".", ",") ;
   }
   return $print_number;
}
?>
Sample use:

<?php
$pur_po_total =  ($pur_po_total + $pur_item_total);
$print_pur_po_total = wims_currency($pur_po_total);
?>

Returns (for example)    $ 44,561.00 or, if a negative ($ 407,250.00)

This way, I use my 1st variable for calculations and my 2nd variable for output.  I'm sure there are better ways to do it,  but this got me back on track.
thomas at weblizards dot de 23-Jan-2009 05:43
It's not explicitly documented; number_format also rounds:

<?php
$numbers = array(0.001, 0.002, 0.003, 0.004, 0.005, 0.006, 0.007, 0.008, 0.009);
foreach ($numbers as $number)
    print $number."->".number_format($number, 2, '.', ',')."<br>";
?>

0.001->0.00
0.002->0.00
0.003->0.00
0.004->0.00
0.005->0.01
0.006->0.01
0.007->0.01
0.008->0.01
0.009->0.01
nospam at nospam dot com 02-Dec-2008 02:08
Simple function to show money as only dollars if no cents, but will show 2 decimals if cents exist.

The 'cents' flag can force to never or always show 2 decimals

<?php

// formats money to a whole number or with 2 decimals; includes a dollar sign in front
function formatMoney($number, $cents = 1) { // cents: 0=never, 1=if needed, 2=always
  if (is_numeric($number)) { // a number
    if (!$number) { // zero
      $money = ($cents == 2 ? '0.00' : '0'); // output zero
    } else { // value
      if (floor($number) == $number) { // whole number
        $money = number_format($number, ($cents == 2 ? 2 : 0)); // format
      } else { // cents
        $money = number_format(round($number, 2), ($cents == 0 ? 0 : 2)); // format
      } // integer or decimal
    } // value
    return '$'.$money;
  } // numeric
} // formatMoney

$a = array(1, 1234, 1.5, 1.234, 2.345, 2.001, 2.100, '1.000', '1.2345', '12345', 0, '0.00');

// show cents if needed ($cents=1)
foreach ($a as $b) echo ('<br />'.$b.' = '.formatMoney($b, 1));
1 = $1
1234 = $1,234
1.5 = $1.50
1.234 = $1.23
2.345 = $2.35
2.001 = $2.00
2.1 = $2.10
1.000 = $1
1.2345 = $1.23
12345 = $12,345
0 = $0
0.00 = $0

// never show cents ($cents=0)
foreach ($a as $b) echo ('<br />'.$b.' = '.formatMoney($b, 0));
1 = $1
1234 = $1,234
1.5 = $2
1.234 = $1
2.345 = $2
2.001 = $2
2.1 = $2
1.000 = $1
1.2345 = $1
12345 = $12,345
0 = $0
0.00 = $0

// always show cents ($cents=2)
foreach ($a as $b) echo ('<br />'.$b.' = '.formatMoney($b, 2));
1 = $1.00
1234 = $1,234.00
1.5 = $1.50
1.234 = $1.23
2.345 = $2.35
2.001 = $2.00
2.1 = $2.10
1.000 = $1.00
1.2345 = $1.23
12345 = $12,345.00
0 = $0.00
0.00 = $0.00

?>

Cheers :)

And remember to always contribute custom functions if they might be useful to the rest of us or future versions of the php language.
samuelpeixoto at gmail dot com 21-Nov-2008 05:05
Exemplo: Example:

<?php
$number = 1234567.896;
echo '1: '.number_format($number, 2, ',', '').'<br>';
echo '2: '.number_format($number, 2, '.', '').'<br>';
echo '3: '.number_format($number, 2, ',', '.').'<br>';
echo '4: '.number_format($number, 2, '.', ',').'<br>';
echo '5: '.number_format($number, 2, ',', ' ').'<br>';
echo '6: '.number_format($number, 2, ',', "'").'<br>';
echo '7: '.number_format($number, 2, '', '').'<br>';
?>

Resultado: Result:

 1: 1234567,90   -> Decimal separado por ,
 2: 1234567.90   -> Decimal separado por .
 3: 1.234.567,90 -> Moeda Brasil, Alemanha
 4: 1,234,567.90 -> Inglês, USA
 5: 1 234 567,90 -> Fran?a
 6: 1'234'567,90 -> Suí?a
 7: 123456790    -> Sem decimal
isapoetra at gmail dot com 15-Jun-2008 06:53
here is the code to convert number to Indonesian text, this code has limitation as is number_format function. sorry for this.
/*
* Created : Iwan Sapoetra - Jun 13, 2008
* Project : Web
* Package : cgaf
*
*/
function terbilang( $num ,$dec=4){
    $stext = array(
        "Nol",
        "Satu",
        "Dua",
        "Tiga",
        "Empat",
        "Lima",
        "Enam",
        "Tujuh",
        "Delapan",
        "Sembilan",
        "Sepuluh",
        "Sebelas"
    );
    $say  = array(
        "Ribu",
        "Juta",
        "Milyar",
        "Triliun",
        "Biliun", // remember limitation of float
        "--apaan---" ///setelah biliun namanya apa?
    );
    $w = "";

    if ($num <0 ) {
        $w  = "Minus ";
        //make positive
        $num *= -1;
    }

    $snum = number_format($num,$dec,",",".");
    die($snum);
    $strnum =  explode(".",substr($snum,0,strrpos($snum,",")));
    //parse decimalnya
    $koma = substr($snum,strrpos($snum,",")+1);

    $isone = substr($num,0,1)  ==1;
    if (count($strnum)==1) {
        $num = $strnum[0];
        switch (strlen($num)) {
            case 1:
            case 2:
                if (!isset($stext[$strnum[0]])){
                    if($num<19){
                        $w .=$stext[substr($num,1)]." Belas";
                    }else{
                        $w .= $stext[substr($num,0,1)]." Puluh ".
                            (intval(substr($num,1))==0 ? "" : $stext[substr($num,1)]);
                    }
                }else{
                    $w .= $stext[$strnum[0]];
                }
                break;
            case 3:
                $w .=  ($isone ? "Seratus" : terbilang(substr($num,0,1)) .
                    " Ratus").
                    " ".(intval(substr($num,1))==0 ? "" : terbilang(substr($num,1)));
                break;
            case 4:
                $w .=  ($isone ? "Seribu" : terbilang(substr($num,0,1)) .
                    " Ribu").
                    " ".(intval(substr($num,1))==0 ? "" : terbilang(substr($num,1)));
                break;
            default:
                break;
        }
    }else{
        $text = $say[count($strnum)-2];
        $w = ($isone && strlen($strnum[0])==1 && count($strnum) <=3? "Se".strtolower($text) : terbilang($strnum[0]).' '.$text);
        array_shift($strnum);
        $i =count($strnum)-2;
        foreach ($strnum as $k=>$v) {
            if (intval($v)) {
                $w.= ' '.terbilang($v).' '.($i >=0 ? $say[$i] : "");
            }
            $i--;
        }
    }
    $w = trim($w);
    if ($dec = intval($koma)) {
        $w .= " Koma ". terbilang($koma);
    }
    return trim($w);
}
//example
echo terbilang(999999999999)."\n";
/**
 * result : Sembilan Ratus Sembilan Puluh Sembilan Milyar Sembilan Ratus Sembilan Puluh Sembilan Juta Sembilan Ratus Sembilan Puluh Sembilan Ribu Sembilan Ratus Sembilan Puluh Sembilan
 */
echo terbilang(9999999999999999);
/**
 * todo : fix this bug pleasese
 * problem : number_format(9999999999999999) <--- 10.000.000.000.000.000,0000
 * Result : Sepuluh Biliun
 */
gabrielu at gmail dot com 08-May-2008 09:54
Using the number_format I'm having some unexpected results.  30% of 14.95 (14.95 * .3) = 4.485.  Now 4.485 rounded to two decimal places should give me 4.49.

Example:
<?php
echo number_format(14.95 * .3, 2, '.', '') . "\n";
echo number_format(4.485, 2, '.', '') . "\n";
?>

Unexpected Results:
4.48
4.49
uliciadrian01 at yahoo dot com 06-Oct-2007 02:34
A simple funtion to format american dollars.

<?php
function formatMoney($money) {
    if($money<1) {
        $money='￠'.$money*100;
    }
    else {
        $dollars=intval($money);
        $cents=$money-$dollars;
        $cents=$cents*100;
        $money='$'.$dollars.' and ￠'.$cents;
    }
    return $money;
}
echo formatmoney('52.342');
?>
This will output: "   $52 and ￠34.2  ".
ted at qtis dot co dot nz 07-Feb-2007 03:38
I use the following to get around the negative zero problem:

<?php
function currency_format($amount, $precision = 2, $use_commas = true, $show_currency_symbol = false, $parentheses_for_negative_amounts = false)
{
    /*
    **    An improvement to number_format.  Mainly to get rid of the annoying behaviour of negative zero amounts.   
    */
    $amount = (float) $amount;
    // Get rid of negative zero
    $zero = round(0, $precision);
    if (round($amount, $precision) == $zero) {
        $amount = $zero;
    }
   
    if ($use_commas) {
        if ($parentheses_for_negative_amounts && ($amount < 0)) {
            $amount = '('.number_format(abs($amount), $precision).')';
        }
        else {
            $amount = number_format($amount, $precision);
        }
    }
    else {
        if ($parentheses_for_negative_amounts && ($amount < 0)) {
            $amount = '('.round(abs($amount), $precision).')';
        }
        else {
            $amount = round($amount, $precision);
        }
    }
   
    if ($show_currency_symbol) {
        $amount = '$'.$amount;  // Change this to use the organization's country's symbol in the future
    }
    return $amount;
}
?>
zulisse at email dot it 06-Feb-2007 02:27
simpler function to convert a number in bytes, kilobytes....

<?php

function bytes($a) {
    $unim = array("B","KB","MB","GB","TB","PB");
    $c = 0;
    while ($a>=1024) {
        $c++;
        $a = $a/1024;
    }
    return number_format($a,($c ? 2 : 0),",",".")." ".$unim[$c];
}

?>

you may also add others units over PeraBytes when the hard disks will reach 1024 PB :)
webmaster at WWW.ELLESSEWEB.NET 24-Nov-2006 06:51
This is a simple and useful function to convert a byte number in a KB  or MB:

<?
function filesize_format ($bytes) {
  $bytes=(float)$bytes;
  if ($bytes<1024){
  $numero=number_format($bytes, 0, ',', '.')." Byte";
  return $numero;
  }
  if ($bytes<1048576){
      $numero=number_format($bytes/1024, 2, ',', '.')." KByte";
  return $numero;
  }
  if ($bytes>=1048576){
      $numero=number_format($bytes/1048576, 2, ',', '.')." MByte";
  return $numero;
  }
}
?>
giovanni dot cappellini at gmail dot com 26-Oct-2006 07:31
About the function of j-a-n at gmx dot de: it's useful, but the argument of the function is $number while the logic of the function requires it to be $in.
04-Jun-2006 12:55
The modification to number_format below does what I actually want it to do, with currency, for example. I want it to show $1.40 and not $1.4 or $1.400 - except in the rare case where I have $1.435 for something, in which case I *don't* want it to round. The ugliness below serves my purpose.

function nof($number,$decimals) {
if (number_format($number,$decimals,'.',',') != $number) {
        return $number;
} else {
        return number_format($number,$decimals,'.',',');
        }
}
mikesabatino at gmail dot com 01-Mar-2006 07:34
<?php
# Function to represent a number like '2nd', '10th', '101st' etc
function text_number($n)
{
    # Array holding the teen numbers. If the last 2 numbers of $n are in this array, then we'll add 'th' to the end of $n
    $teen_array = array(11, 12, 13, 14, 15, 16, 17, 18, 19);
   
    # Array holding all the single digit numbers. If the last number of $n, or if $n itself, is a key in this array, then we'll add that key's value to the end of $n
    $single_array = array(1 => 'st', 2 => 'nd', 3 => 'rd', 4 => 'th', 5 => 'th', 6 => 'th', 7 => 'th', 8 => 'th', 9 => 'th', 0 => 'th');
   
    # Store the last 2 digits of $n in order to check if it's a teen number.
    $if_teen = substr($n, -2, 2);
   
    # Store the last digit of $n in order to check if it's a teen number. If $n is a single digit, $single will simply equal $n.
    $single = substr($n, -1, 1);
   
    # If $if_teen is in array $teen_array, store $n with 'th' concantenated onto the end of it into $new_n
    if ( in_array($if_teen, $teen_array) )
    {
        $new_n = $n . 'th';
    }
    # $n is not a teen, so concant the appropriate value of it's $single_array key onto the end of $n and save it into $new_n
    elseif ( $single_array[$single] )
    {
        $new_n = $n . $single_array[$single];   
    }
   
    # Return new
    return $new_n;
}
?>
MarcM 20-Feb-2006 10:03
For Zero fill - just use the sprintf() function

$pr_id = 1;
$pr_id = sprintf("%03d", $pr_id);
echo $pr_id;

//outputs 001
-----------------

$pr_id = 10;
$pr_id = sprintf("%03d", $pr_id);
echo $pr_id;

//outputs 010
-----------------

You can change %03d to %04d, etc.
Jeroen de Bruijn [NL] 01-Oct-2005 03:02
If you want to display a number ending with ,- (like 200,-) when there are no decimal characters and display the decimals when there are decimal characters i use:

function DisplayDouble($value)
  {
  list($whole, $decimals) = split ('[.,]', $value, 2);
  if (intval($decimals) > 0)
    return number_format($value,2,".",",");
  else
    return number_format($value,0,".",",") .",-";
  }
marc dot vanwoerkom at fernuni-hagen dot de 14-Jul-2005 06:53
See also the documentation for localeconv, which will provide values for decimal point and thousands separator from the C standard library.

Of course localeconv features many more locale information, like indicating to put the negative sign behind the value for some locale settings which can't be used to customize present number_format.
venimus777 at yahoo dot com 08-Jun-2005 05:25
You could use the following regular expression to divide
a number into parts:

$1-number without fractal part
$2-fractal part
$3-first 2 digits of the fractal part
$4-rest of the fractal part

the regex removes any leading and trailing symbols and leading zeros. It doesnt validate the number, so 12 41 is considered to be correct input!

english notation:
/^.*?[0]*([\d\s]+)(([\.][\d]{0,2})([\d]*))?.*?$/

french notation:
/^.*?[0]*([\d\s]+)(([\,][\d]{0,2})([\d]*))?.*?$/

<?php
// truncate the fractal part up to 2 digits of an "english number":
$number = '01,234.50789';
$trunc = preg_replace(
    '/^.*?[0]*([\d\,]+)(([\.][\d]{0,2})([\d]*))?.*?$/',
    '$1$3',
    $number
);
echo $trunc;
?>

Outputs:
1,234.50

$number='e00012 41.100001e-4fasfd';
would output:
12 41.10
woodynadobhar at hotmail dot com 17-May-2005 09:04
What do you do if some of your numbers have decimal places, and some don't?  You can switch between functions, but if you're building it in a loop, that's not a good solution.  Instead, we have the same as below, with a slight change:

function number_format_unlimited_precision($number,$decimal = '.'){
    $broken_number = explode($decimal,$number);
    if($broken_number[1]==0){
        return number_format($broken_number[0]);
    }else{
        return number_format($broken_number[0]).$decimal.$broken_number[1];
    };
};
stm555 at hotmail dot com 27-Apr-2005 08:54
I ran across an issue where I wanted to keep the entered precision of a real value, without arbitrarily rounding off what the user had submitted.

I figured it out with a quick explode on the number before formatting. I could then format either side of the decimal.

<?php
      function number_format_unlimited_precision($number,$decimal = '.')
      {
           $broken_number = explode($decimal,$number);
           return number_format($broken_number[0]).$decimal.$broken_number[1];
      }
?>
mike at phpeeb dot com 02-Apr-2005 01:13
Since number_format returns a string, you must perform all mathmatical functions on the number before applying number_format:

<?
$total = 100;
$total = number_format($total, 2);
$shipping = 20.00;
$grand_total = $total + $shipping;

echo number_format($grand_total, 2);

/* The above will return 21.00 because $total is now a string, and no longer an integer or float. Since a string will have a value of 1,  the addition of the two will return 21 and not 120. */

$total = 100;
$shipping = 20.00;
$grand_total = $total + $shipping;

echo number_format($grand_total, 2);

/* This works, and will return 120.00 as intended */

?>
php at mijav dot dk 31-Mar-2005 06:25
A bug was issued that -0,00 is invalid output from number_format(), but the bug was rejected since the number "-0.0000000000000000001E-999 is about -0". And the developer felt this was correct output.

Please beware of negative numbers close to zero, as they might produce this unusable (and in my opinion incorrect/off-description) output.
keyg at auralplanet dot com 22-Nov-2004 06:56
if you want &nbsp; as a separator and use windows charset this piece of code may help:

<?php
$number=number_format($number,2,'.',chr(0xA0));
?>
brandonprudent at yahoo dot com 10-Oct-2004 11:52
To convert numbers to thier textual representations, you can use an adapted version of the Number::Spell Perl module. The PHP conversion can be found here: http://pear.php.net/package/Numbers_Words
Svein Tjonndal (sveint at yahoo dot com) 14-Sep-2004 07:18
If you use space as a separator, it will break on that space in HTML tables...

Furthermore, number_format doesn't like '&nbsp;' as a fourth parameter. I wrote the following function to display the numbers in an HTML table.

  function numberfix($number)
  {
    $number = number_format($number,0,","," ");
    return str_replace(" ", "&nbsp;", $number);
  }

For use in:
<table><tr><td><?php echo $number; ?></td></tr></table>
chandu at chandu dot org 07-Mar-2004 05:29
People here in India are more used to counting money in Lakhs & Crores .. so here is the code for formatting the commas with thousands for the first time and then with hundred multiples from there after.

Ex: 1234567  ->  12,34,567

<?php

function makecomma($input)
{
    // This function is written by some anonymous person - I got it from Google
    if(strlen($input)<=2)
    { return $input; }
    $length=substr($input,0,strlen($input)-2);
    $formatted_input = makecomma($length).",".substr($input,-2);
    return $formatted_input;
}

function formatInIndianStyle($num){
    // This is my function
    $pos = strpos((string)$num, ".");
    if ($pos === false) { $decimalpart="00";}
    else { $decimalpart= substr($num, $pos+1, 2); $num = substr($num,0,$pos); }

    if(strlen($num)>3 & strlen($num) <= 12){
                $last3digits = substr($num, -3 );
                $numexceptlastdigits = substr($num, 0, -3 );
                $formatted = makecomma($numexceptlastdigits);
                $stringtoreturn = $formatted.",".$last3digits.".".$decimalpart ;
    }elseif(strlen($num)<=3){
                $stringtoreturn = $num.".".$decimalpart ;
    }elseif(strlen($num)>12){
                $stringtoreturn = number_format($num, 2);
    }

    if(substr($stringtoreturn,0,2)=="-,"){$stringtoreturn = "-".substr($stringtoreturn,2 );}

    return $stringtoreturn;
}

$num = 1234567;
echo  formatInIndianStyle($num);

?>
sgj at dr dot com 17-May-2003 06:04
Just an observation:
The number_format rounds the value of the variable.

$val1 = 1.233;
$val2 = 1.235;
$val3 = 1.237;

echo number_format($val1,2,",","."); // returns: 1,23
echo number_format($val2,2,",","."); // returns: 1,24
echo number_format($val3,2,",","."); // returns: 1,24
Theo Diem 24-Mar-2003 01:45
formatting numbers may be more easy if u use number_format function.

I also wrote this :
function something($number)
{
    $locale = localeconv();
    return number_format($number,
       $locale['frac_digits'],
        $locale['decimal_point'],
        $locale['thousands_sep']);
}

hope this helps =)
[]'s

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