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sqlite_field_name

SQLiteResult::fieldName

SQLiteUnbuffered::fieldName

(PHP 5 < 5.4.0, PECL sqlite >= 1.0.0)

sqlite_field_name -- SQLiteResult::fieldName -- SQLiteUnbuffered::fieldName — Returns the name of a particular field

说明

sqlite_field_name ( resource $result , int $field_index ) : string

面向对象风格 (method):

SQLiteResult::fieldName ( int $field_index ) : string

SQLiteUnbuffered::fieldName ( int $field_index ) : string

Given the ordinal column number, field_index, sqlite_field_name() returns the name of that field in the result set result.

参数

result: The SQLite result resource. This parameter is not required when using the object-oriented method.
field_index: The ordinal column number in the result set.

返回值

Returns the name of a field in an SQLite result set, given the ordinal column number; FALSE on error.

由 SQLITE_ASSOC 与 SQLITE_BOTH 返回的列名会依照 sqlite.assoc_case 配置选项的值决定大小写。

User Contributed Notes

Jan Holeek 12-Jan-2011 05:27


This code works with SQlite version 3 databases. 

<?php

function sqlite_field_names($dbfile, $tablename){

    try

      {

    $db = new PDO("sqlite:".$dbfile);

    $sql=$db->query("SELECT sql FROM sqlite_master WHERE tbl_name='".$tablename."'");

    foreach($sql as $row)

        {

        $fields = $row["sql"];

        }

    $db = NULL;

   }

   catch(PDOException $e)

   {

    print "Exception : ".$e->getMessage();

   }

    $cut=strtok($fields,"(");

    while($fieldnames[]=strtok(",")) {};

    array_pop($fieldnames);

    foreach($fieldnames as $no => $field)

        if (strpos($field, "PRIMARY KEY")){

            strtok($field,"(");

            $primary=strtok(")");

            unset($fieldnames[$no]);

        } else

            $fieldnames[$no]=strtok($field, " ");

    return $fieldnames;

}



print_r(array_values(sqlite_field_names($dbfile, $tablename)));

?>

admin at psychonautical dot org 09-Nov-2010 11:58


It's not the most elegant way, but it works:



<?php

function sqlite_field_names($db, $tablename){

    $sq5=sqlite_single_query($db, "SELECT sql FROM sqlite_master WHERE tbl_name='".$tablename."'", SQLITE_NUM);

    $kommando=$sq5[0];

    $cut=strtok($kommando,"(");

    while($fieldnames[]=strtok(",")) {};

    array_pop($fieldnames);

    foreach($fieldnames as $no => $field)

        if (strpos($field, "PRIMARY KEY")){

            strtok($field,"(");

            $primary=strtok(")");

            unset($fieldnames[$no]);

        } else

            $fieldnames[$no]=strtok($field, " ");

    return $fieldnames;

}

?>

rrf5000 at psu dot edu 22-Jun-2007 01:03


While working with SQLite using its object-oriented mode, I found need to display a column/field name without knowing what it was in advance.  I couldn't find any examples on the Internet, just this document.  So, for anyone who happens to need to do this, here's an example.



<?php



$db = "db/database.sqlite";



// create new database (OO interface)

$dbo = new SQLiteDatabase("$db");



// create table foo and insert sample data

$dbo->query("

 CREATE TABLE foo(id INTEGER PRIMARY KEY, name CHAR(255));

 INSERT INTO foo (name) VALUES('Ilia1');

 INSERT INTO foo (name) VALUES('Ilia2');

 INSERT INTO foo (name) VALUES('Ilia3');

");



$query = "SELECT * FROM foo;";



$result = $dbo->query($query) or die("Error in query");



echo "

<table border='1' cellpadding='10'>

 <tr>

  <td>".$result->fieldName(0)."</td>

  <td>".$result->fieldName(1)."</td>

 </tr>";



// iterate through the retrieved rows

while ($result->valid()) {

  // fetch current row

  $row = $result->current();

  echo "

 <tr>

  <td>".$row[0]."</td>

  <td>".$row[1]."</td>

 </tr>";

  // proceed to next row

  $result->next();

}



echo "</table>";



?>

php教程 php手册 php手册

sqlite_field_name

SQLiteResult::fieldName

SQLiteUnbuffered::fieldName

说明

参数

返回值

User Contributed Notes

php教程

php手册