(PHP 5 < 5.4.0, PECL sqlite >= 1.0.0)
sqlite_num_rows -- SQLiteResult::numRows — Returns the number of rows in a buffered result set
$result
) : int面向对象风格 (method):
Returns the number of rows in the buffered result
set.
resultThe SQLite result resource. This parameter is not required when using the object-oriented method.
Note:
此函数不能用于未缓冲的结果句柄。
Returns the number of rows, as an integer.
Example #1 Procedural example
<?php
$db = sqlite_open('mysqlitedb');
$result = sqlite_query($db, "SELECT * FROM mytable WHERE name='John Doe'");
$rows = sqlite_num_rows($result);
echo "Number of rows: $rows";
?>
Example #2 Object-oriented example
<?php
$db = new SQLiteDatabase('mysqlitedb');
$result = $db->query("SELECT * FROM mytable WHERE name='John Doe'");
$rows = $result->numRows();
echo "Number of rows: $rows";
?>
//I don't know about you. But for me this is what I had to do
$db = new SQLite3('databasename.db');
$result = $db->query("SELECT * FROM table_name");
$number_of_rows = 0;//for now
while($row = $result->fetchArray()) {
$number_of_rows += 1;
}
echo "Number of rows: $number_of_rows";
@rezaamya
$db = new SQLite3('databasename.db');
$result = $db->query("SELECT * FROM users");
$rows = count ($result);
echo "Number of rows: $rows";
$rows value should always be 1
... even if the query is invalid
I tested that on
SQLite Library 3.7.7.1
neither of "sqlite_num_rows($result)" and "$result->numRows()" is not working on SQLite3 !
you should use this way:
$db = new SQLite3('databasename.db');
$result = $db->query("SELECT * FROM users");
$rows = count ($result);
echo "Number of rows: $rows";