php教程

使用命名空间：别名/导入

(PHP 5 >= 5.3.0, PHP 7)

允许通过别名引用或导入外部的完全限定名称，是命名空间的一个重要特征。这有点类似于在类 unix 文件系统中可以创建对其它的文件或目录的符号连接。

所有支持命名空间的PHP版本支持三种别名或导入方式：为类名称使用别名、为接口使用别名或为命名空间名称使用别名。PHP 5.6开始允许导入函数或常量或者为它们设置别名。

在PHP中，别名是通过操作符 use 来实现的. 下面是一个使用所有可能的五种导入方式的例子：

Example #1 使用use操作符导入/使用别名

<?php
namespace foo;
use My\Full\Classname as Another;

// 下面的例子与 use My\Full\NSname as NSname 相同
use My\Full\NSname;

// 导入一个全局类
use ArrayObject;

// importing a function (PHP 5.6+)
use function My\Full\functionName;

// aliasing a function (PHP 5.6+)
use function My\Full\functionName as func;

// importing a constant (PHP 5.6+)
use const My\Full\CONSTANT;

$obj = new namespace\Another; // 实例化 foo\Another 对象
$obj = new Another; // 实例化 My\Full\Classname　对象
NSname\subns\func(); // 调用函数 My\Full\NSname\subns\func
$a = new ArrayObject(array(1)); // 实例化 ArrayObject 对象
// 如果不使用 "use \ArrayObject" ，则实例化一个 foo\ArrayObject 对象
func(); // calls function My\Full\functionName
echo CONSTANT; // echoes the value of My\Full\CONSTANT
?>
注意对命名空间中的名称（包含命名空间分隔符的完全限定名称如 Foo\Bar以及相对的不包含命名空间分隔符的全局名称如 FooBar）来说，前导的反斜杠是不必要的也不推荐的，因为导入的名称必须是完全限定的，不会根据当前的命名空间作相对解析。

为了简化操作，PHP还支持在一行中使用多个use语句

Example #2 通过use操作符导入/使用别名，一行中包含多个use语句

<?php
use My\Full\Classname as Another, My\Full\NSname;

$obj = new Another; // 实例化 My\Full\Classname 对象
NSname\subns\func(); // 调用函数 My\Full\NSname\subns\func
?>

导入操作是在编译执行的，但动态的类名称、函数名称或常量名称则不是。

Example #3 导入和动态名称

<?php
use My\Full\Classname as Another, My\Full\NSname;

$obj = new Another; // 实例化一个 My\Full\Classname 对象
$a = 'Another';
$obj = new $a;      // 实际化一个 Another 对象
?>

另外，导入操作只影响非限定名称和限定名称。完全限定名称由于是确定的，故不受导入的影响。

Example #4 导入和完全限定名称

<?php
use My\Full\Classname as Another, My\Full\NSname;

$obj = new Another; // instantiates object of class My\Full\Classname
$obj = new \Another; // instantiates object of class Another
$obj = new Another\thing; // instantiates object of class My\Full\Classname\thing
$obj = new \Another\thing; // instantiates object of class Another\thing
?>

Scoping rules for importing

The use keyword must be declared in the outermost scope of a file (the global scope) or inside namespace declarations. This is because the importing is done at compile time and not runtime, so it cannot be block scoped. The following example will show an illegal use of the use keyword:

Example #5 Illegal importing rule

<?php
namespace Languages;

class Greenlandic
{
    use Languages\Danish;

    ...
}
?>

Note:

Importing rules are per file basis, meaning included files will NOT inherit the parent file's importing rules.

User Contributed Notes

Dhairya Lakhera 27-Jul-2019 01:41
namespace test{

    use test\xyz\tikku;
    use test\xyz\tikku as class_alias;
    use function test\xyz\tikku\foo;
    use function test\xyz\tikku\foo as func_alias;
    use const test\xyz\tikku\ABC;
    use const test\xyz\tikku\ABC as const_alias;
   

   

    $obj=new tikku;
    $obj->Display();  // I am in  test\xyz namespace

    $obj=new tikku\dhairya;
    $obj->Display();   // I am in test\xyz\tikku namespace

    $obj=new class_alias\dhairya;
    $obj->Display();   // I am in test\xyz\tikku namespace

    $obj=new \class_alias\dhairya;
    $obj->Display();  // I am in class_alias namespace

}

namespace test\xyz{

   class tikku{
    function Display(){
        echo "I am in ".__namespace__." namespace<br/><hr/>";
    }
   }
}

namespace test\xyz\tikku{

   class dhairya{
    function Display(){
        echo "I am in ".__namespace__." namespace<br/><hr/>";
    }
   }
}

namespace class_alias{

   class dhairya{
    function Display(){
        echo "I am in ".__namespace__." namespace<br/><hr/>";
    }
   }
}
www.codewars.com 07-Jun-2019 01:59
amazing!!

use function strval as numberToString;

var_dump(numberToString(123));

//print
//string(3) "123"
Joey 29-Mar-2018 02:25
For those hoping for an easy fix of DRY with {} unfortunately you can't nest it or do anything cool with it. In case you can only have one per use and if you don't have one then the whole use is assumed to be wrapped in brackets. That means if you do have one you can't use , as normal with use!

Not possible:

    use A\B\C\{
            D, E,
            F\{X, Y, Z}
        },
        X\Y\Z,
        H\{
            I\{
                Y\Y\Y\Y\Y,
                Z, H, E
            },
            J\{
                A\{
                    G\H\J
                    B\N
                },
                G\H\J
            }
        };
Mawia HL 21-Oct-2017 05:03
Here is a handy way of importing classes, functions and conts using a single use keyword:

<?php
use Mizo\Web\ {
   Php\WebSite,
   Php\KeyWord,
   Php\UnicodePrint,
   JS\JavaScript,
   function JS\printTotal,
   function JS\printList,
   const JS\BUAIKUM,
   const JS\MAUTAM
};
?>
xzero at elite7hackers dot net 04-May-2017 11:13
I couldn't find answer to this question so I tested myself.
I think it's worth noting:

<?php
use ExistingNamespace\NonExsistingClass;
use ExistingNamespace\NonExsistingClass as whatever;
use NonExistingNamespace\NonExsistingClass;
use NonExistingNamespace\NonExsistingClass as whatever;
?>

None of above will actually cause errors unless you actually try to use class you tried to import.

<?php
// And this code will issue standard PHP error for non existing class.
use ExistingNamespace\NonExsistingClass as whatever;
$whatever = new whatever();
?>
ZhangLiang 15-Feb-2017 06:16
In Chinese,there is an error in translation:
// 如果不使用 "use \ArrayObject" ，则实例化一个 foo\ArrayObject 对象
it should be
// 如果不使用 "use ArrayObject" ，则实例化一个 foo\ArrayObject 对象

/*********************************************/
中文下翻译有错误
// 如果不使用 "use \ArrayObject" ，则实例化一个 foo\ArrayObject 对象
这句话应该是
// 如果不使用 "use ArrayObject" ，则实例化一个 foo\ArrayObject 对象
ultimater at gmail dot com 30-Sep-2016 10:53
Note that "use" importing/aliasing only applies to the current namespace block.

<?php

namespace SuperCoolLibrary
{
    class Meta
    {
        static public function getVersion()
        {
            return '2.7.1';
        }
    }
}

namespace
{
    use SuperCoolLibrary\Meta;
    echo Meta::getVersion();//outputs 2.7.1
}

namespace
{
    echo Meta::getVersion();//fatal error
}

?>

To get the expected behavior, you'd use:
class_alias('SuperCoolLibrary\Meta','Meta');
dominic_mayers at yahoo dot com 20-Sep-2016 11:18
To clarify the distinction between inserting a trait in a class and importing a trait in a namespace, here is an example where we first import and then insert a trait.

<?php
namespace ns1;
trait T {
  static $a = "In T";
}

namespace ns2;
use ns1\T; // Importing the name of trait ns1\T  in the namespace ns2
class C {
  use T; // Inserting trait T in the class C, making use of the imported name.
} 

namespace main;
use ns2\C;
echo C::$a; // In T;
dominic_mayers at yahoo dot com 20-Sep-2016 10:50
The keyword "use" has been recycled for three distinct applications:
1- to import/alias classes, traits, constants, etc. in namespaces,
2- to insert traits in classes,
3- to inherit variables in closures.
This page is only about the first application: importing/aliasing. Traits can be inserted in classes, but this is different from importing a trait in a namespace, which cannot be done in a block scope, as pointed out in example 5. This can be confusing, especially since all searches for the keyword "use" are directed to the documentation here on importing/aliasing.
me at ruslanbes dot com 31-Mar-2016 07:34
Note the code `use ns1\c1` may refer to importing class `c1` from namespace `ns1` as well as importing whole namespace `ns1\c1` or even import both of them in one line. Example:

<?php
namespace ns1;

class c1{}

namespace ns1\c1;

class c11{}

namespace main;

use ns1\c1;

$c1 = new c1();
$c11 = new c1\c11();

var_dump($c1); // object(ns1\c1)#1 (0) { }
var_dump($c11); // object(ns1\c1\c11)#2 (0) { }
kelerest123 at gmail dot com 10-Mar-2015 05:50
For the fifth example (example #5):

When in block scope, it is not an illegal use of use keyword, because it is used for sharing things with traits.
anon 30-Jan-2014 09:08
The <?php use ?> statement does not load the class file. You have to do this with the <?php require ?> statement or by using an autoload function.
k at webnfo dot com 07-Apr-2013 01:32
Note that you can not alias global namespace:

use \ as test;

echo test\strlen('');

won't work.
Anonymous 03-Apr-2013 10:02
The last example on this page shows a possibly incorrect attempt of aliasing, but it is totally correct to import a trait \Languages\Languages\Danish.
cl 11-Mar-2013 12:59
Something that is not immediately obvious, particular with PHP 5.3, is that namespace resolutions within an import are not resolved recursively.  i.e.: if you alias an import and then use that alias in another import then this latter import will not be fully resolved with the former import.

For example:
use \Controllers as C;
use C\First;
use C\Last;

Both the First and Last namespaces are NOT resolved as \Controllers\First or \Controllers\Last as one might intend.
x at d dot a dot r dot k dot REMOVEDOTSANDTHIS dot gray dot org 02-Jan-2013 05:13
You are allowed to "use" the same resource multiple times as long as it is imported under a different alias at each invocation.

For example:

<?php
use Lend;
use Lend\l1;
use Lend\l1 as l3;
use Lend\l2;
use Lend\l1\Keller;
use Lend\l1\Keller as Stellar;
use Lend\l1\Keller as Zellar;
use Lend\l2\Keller as Dellar;

...

?>

In the above example, "Keller", "Stellar", and "Zellar" are all references to "\Lend\l1\Keller", as are "Lend\l1\Keller", "l1\Keller", and "l3\Keller".
c dot 1 at smithies dot org 14-Aug-2011 03:26
If you are testing your code at the CLI, note that namespace aliases do not work!

(Before I go on, all the backslashes in this example are changed to percent signs because I cannot get sensible results to display in the posting preview otherwise. Please mentally translate all percent signs henceforth as backslashes.)

Suppose you have a class you want to test in myclass.php:

<?php
namespace my%space;
class myclass {
 // ...
}
?>

and you then go into the CLI to test it. You would like to think that this would work, as you type it line by line:

require 'myclass.php';
use my%space%myclass; // should set 'myclass' as alias for 'my%space%myclass'
$x = new myclass; // FATAL ERROR

I believe that this is because aliases are only resolved at compile time, whereas the CLI simply evaluates statements; so use statements are ineffective in the CLI.

If you put your test code into test.php:
<?php
require 'myclass.php';
use my%space%myclass;
$x = new myclass;
//...
?>
it will work fine.

I hope this reduces the number of prematurely bald people.
thinice at gmail.com 01-Dec-2010 10:07
Because imports happen at compile time, there's no polymorphism potential by embedding the use keyword in a conditonal.

e.g.:

<?php
if ($objType == 'canine') {
  use Animal\Canine as Beast;
}
if ($objType == 'bovine') {
  use Animal\Bovine as Beast;
}

$oBeast = new Beast;
$oBeast->feed();
?>

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