php教程

min

(PHP 4, PHP 5, PHP 7)

min找出最小值

说明

min ( array $values ) : mixed
min ( mixed $value1 , mixed $value2 [, mixed $... ] ) : mixed

如果仅有一个参数且为数组,min() 返回该数组中最小的值。如果给出了两个或更多参数, min() 会返回这些值中最小的一个。

Note:

PHP 会将非数值的 string 当成 0,但如果这个正是最小的数值则仍然会返回一个字符串。如果多个参数都求值为 0 且是最小值,min() 会返回按字母表顺序最小的字符串,如果其中没有字符串的话,则返回数值的 0

参数

values

包含值的数组。

value1

Any comparable value.

value2

Any comparable value.

...

Any comparable value.

返回值

min() 返回参数中数值最小的。

范例

Example #1 min() 用法的例子

<?php
echo min(23167);  // 1
echo min(array(245)); // 2

echo min(0'hello');     // 0
echo min('hello'0);     // hello
echo min('hello', -1);    // -1

// 对多个数组,min 从左向右比较。
// 因此在本例中:2 == 2,但 4 < 5
$val min(array(248), array(251)); // array(2, 4, 8)

// 如果同时给出数组和非数组作为参数,则不可能返回数组,因为
// 数组被视为最大的
$val min('string', array(257), 42);   // string
?>

参见

  • max() - 找出最大值
  • count() - 计算数组中的单元数目,或对象中的属性个数

User Contributed Notes

8ilO 19-Apr-2017 03:21
A min_by function:
<?php
function min_by(Array $arr, Callable $func){
   
$mapped = array_map($func, $arr);
    return
$arr[array_search(min($mapped), $mapped)];
}
$a = ["albatross""dog""horse"];
echo
min_by($a, "strlen"); // dog
?>
volch5 at gmail dot com 07-May-2014 04:10
min() (and max()) on DateTime objects compares them like dates (with timezone info) and returns DateTime object.
<?php
$dt1
= new DateTime('2014-05-07 18:53', new DateTimeZone('Europe/Kiev'));
$dt2 = new DateTime('2014-05-07 16:53', new DateTimeZone('UTC'));
echo
max($dt1,$dt2)->format(DateTime::RFC3339) . PHP_EOL; // 2014-05-07T16:53:00+00:00
echo min($dt1,$dt2)->format(DateTime::RFC3339) . PHP_EOL; // 2014-05-07T18:53:00+03:00
?>

It works at least 5.3.3-7+squeeze17
Teelevision 13-Oct-2013 04:09
A function that returns the lowest integer that is not 0.
<?php
/* like min(), but casts to int and ignores 0 */
function min_not_null(Array $values) {
    return
min(array_diff(array_map('intval', $values), array(0)));
}
?>
hava82 at gmail dot com 26-Sep-2011 12:35
Here is function can find min by array key

<?php
function min_by_key($arr, $key){
   
$min = array();
    foreach (
$arr as $val) {
        if (!isset(
$val[$key]) and is_array($val)) {
           
$min2 = min_by_key($val, $key);
           
$min[$min2] = 1;
        } elseif (!isset(
$val[$key]) and !is_array($val)) {
            return
false;
        } elseif (isset(
$val[$key])) {
           
$min[$val[$key]] = 1;
        }
    }
    return
min( array_keys($min) );
}
?>
php at keith tyler dot com 23-Nov-2010 01:03
If NAN is the first argument to min(), the second argument will always be returned.

If NAN is the second argument, NAN will always be returned.

The relationship is the same but inverted for max().

<?php
// \n's skipped for brevity
print max(0,NAN);
print
max(NAN,0);
print
min(0,NAN);
print
min(NAN,0);
?>

Returns:
0
NAN
NAN
0
matt at borjawebs dot com 13-Nov-2010 01:18
A condensed version (and possible application) of returning an array of array keys containing the same minimum value:

<?php
// data
$min_keys = array();
$player_score_totals = array(
'player1' => 300,
'player2' => 301,
'player3' => 302,
'player4' => 301,
...
);

// search for array keys with min() value
foreach($player_score_totals as $playerid => $score)
    if(
$score == min($player_score_totals)) array_push($min_keys, $playerid);

print_r($min_keys);
?>
Err 05-Oct-2009 04:32
When using a variable with an array that has a list of numbers, put just the variable in min(). Don't use integer index's. Seems pretty straight forward now, but I wasn't used to just putting down the variable for an array in functions.

<?php
  $list
= array(9,5,4,6,2,7);
  echo
min($list); // display 2
?>
DO 03-Jul-2008 03:23
I've modified the bugfree min-version to ignore NULL values (else it returns 0).

<?php
function min_mod () {
 
$args = func_get_args();
 
  if (!
count($args[0])) return false;
  else {
   
$min = false;
    foreach (
$args[0] AS $value) {
      if (
is_numeric($value)) {
       
$curval = floatval($value);
        if (
$curval < $min || $min === false) $min = $curval;
      }
    }
  }
 
  return
$min;  
}
?>
harmor 21-Feb-2008 09:58
A way to bound a integer between two values is:

function bound($x, $min, $max)
{
     return min(max($x, $min), $max);
}

which is the same as:

$tmp = $x;
if($tmp < $min)
{
    $tmp = $min;
}
if($tmp > $max)
{
     $tmp = $max;
}
$y = $tmp;

So if you wanted to bound an integer between 1 and 12 for example:

Input:
$x = 0;
echo bound(0, 1, 12).'<br />';
$x = 1;
echo bound($x, 1, 12).'<br />';
$x = 6;
echo bound($x, 1, 12).'<br />';
$x = 12;
echo bound($x, 1, 12).'<br />';
$x = 13;
echo bound($x, 1, 12).'<br />';

Output:
1
1
6
12
12
piotr_sobolewski at o2 dot nospampleasenono dot pl 07-Nov-2007 08:11
Be very careful when your array contains both strings and numbers. This code works strange (even though explainable) way:
var_dump(max('25.1.1', '222', '99'));
var_dump(max('2.1.1', '222', '99'));
dave at dtracorp dot com 13-Aug-2006 08:30
empty strings '' will also return false or 0, so if you have something like

$test = array('', 1, 5, 8, 44, 22);

'' will be returned as the lowest value

if you only want to get the lowest number, you'll have to resort to the old fashioned loop

// default minimum value
$minVal = 100;
foreach ($test as $value) {
if (is_numeric($value) && $value < $minVal) {
$minVal = $value;
}
johnphayes at gmail dot com 02-May-2006 09:26
Regarding boolean parameters in min() and max():

(a) If any of your parameters is boolean, max and min will cast the rest of them to boolean to do the comparison.
(b) true > false
(c) However, max and min will return the actual parameter value that wins the comparison (not the cast).

Here's some test cases to illustrate:

1.  max(true,100)=true
2.  max(true,0)=true
3.  max(100,true)=100
4.  max(false,100)=100
5.  max(100,false)=100
6.  min(true,100)=true
7.  min(true,0)=0
8.  min(100,true)=100
9.  min(false,100)=false
10. min(100,false)=false
11. min(true,false)=false
12. max(true,false)=true
steffen at morkland dot com 16-Mar-2006 02:16
> NEVER EVER use this function with boolean variables !!!
> Or you'll get something like this: min(true, 1, -2) == true;

> Just because of:
> min(true, 1, -2) == min(min(true,1), -2) == min(true, -2) == true;

It is possible to use it with booleans, there is is just one thing, which you need to keep in mind, when evaluating using the non strict comparison (==) anyting that is not bool false, 0 or NULL is consideret true eg.:
(5 == true) = true;
(0 == true) = false;
true is also actually anything else then 0, false and null. However when true is converted to a string or interger true == 1, therefore when sorting true = 1. But if true is the maximum number bool true is returned. so to be sure, if you only want to match if true is the max number remember to use the strict comparison operater ===
31-Jan-2006 09:37
NEVER EVER use this function with boolean variables !!!
Or you'll get something like this: min(true, 1, -2) == true;

Just because of:
min(true, 1, -2) == min(min(true,1), -2) == min(true, -2) == true;

You are warned !
alx5000 at walla dot com 12-Jan-2005 05:16
If you want min to return zero (0) when comparing to a string, try this:

<?php
min
(3,4,";");  // ";"
min(0,min(3,4,";")) // 0
?>
nonick AT 8027 DOT org 24-Jan-2004 07:43
I tested this with max(), but I suppose it applies to min() too: If you are working with numbers, then you can use:
 
    $a = ($b < $c) ? $b : $c;
 
 which is somewhat faster (roughly 16%) than
 
    $a = min($b, $c);
 
 I tested this on several loops using integers and floats, over 1 million iterations.
 
 I'm running PHP 4.3.1 as a module for Apache 1.3.27.
browne at bee why you dot ee dee you 16-Dec-2003 02:30
min() can be used to cap values at a specific value. For instance, if you're grading papers and someone has some extra credit, but  that shouldn't make it to the final score:

$pts_possible = 50;
$score = 55;

// Percent will equal 1 if $score/$pts_possible is greater than 1
$percent = min($score/$pts_possible,1);

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